Given #y = x^3 x^2 5x# You can use the first derivative test or the second derivative test The second derivative test is straight forward if the second derivative is easy to find It does not require setting up intervals and testing a value in each interval Using the Second Derivative Test #f(x) = x^3 x^2 5x# #f'(x) = 3x^2 2x 5#SEE THE FOLLOWING EXAMPLE AND TRYIF STILL IN DIFFICULTY PLEASE COME BACK Y INTERCEPT IS DETERMINED BY THE POINTS WHERE THE CURVE INTERSECTS X AXISHENCE THIS IS OBTAINED BY EQUATING THE EQNA specialty in mathematical expressions is that the multiplication sign can be left out sometimes, for example we write "5x" instead of "5*x" The Derivative Calculator has to detect these cases and insert the multiplication sign The parser is implemented in JavaScript, based on the Shuntingyard algorithm, and can run directly in the browser
Prove That The Tangent To The Curve Y X 2 5x 6 At The Points P 2 0 And Q 3 0 Are At Right Angles Mathematics Topperlearning Com 8s4a3fjj
